[haskeline] #81: haskeline assumes all characters have width = 1

haskeline haskeline at projects.haskell.org
Sat May 16 11:59:21 EDT 2009


#81: haskeline assumes all characters have width = 1
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Reporter:  guest   |        Owner:     
    Type:  defect  |       Status:  new
Priority:  major   |    Milestone:     
 Version:  0.6     |   Resolution:     
Keywords:          |  
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Comment (by judah):

 Can you give some examples of double-wide or combining characters?  Any
 suggestions on how Haskeline could determine the width of a character?

-- 
Ticket URL: <http://trac.haskell.org/haskeline/ticket/81#comment:1>
haskeline <http://example.org/>
My example project


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